from threading import Thread,RLockimport timemutexA=mutexB=RLock() #一个线程拿到锁，counter加1,该线程内又碰到加锁的情况，则counter继续加1，  #这期间所有其他线程都只能等待，等待该线程释放所有锁，即counter递减到0为止class MyThread(Thread):    def run(self):        self.func1()        self.func2()    def func1(self):        mutexA.acquire()        print('\033[41m%s 拿到A锁\033[0m' %self.name)        mutexB.acquire()        print('\033[42m%s 拿到B锁\033[0m' %self.name)        mutexB.release()        mutexA.release()    def func2(self):        mutexB.acquire()        print('\033[43m%s 拿到B锁\033[0m' %self.name)        time.sleep(2)        mutexA.acquire()        print('\033[44m%s 拿到A锁\033[0m' %self.name)        mutexA.release()        mutexB.release()if __name__ == '__main__':    for i in range(10):        t=MyThread()        t.start()